Sederhanakan operasi bentuk akar berikut a.3√2+√8 b. 12√3 - 2√27
![]()
Penjelasan dengan langkah-langkah:
a).
[tex]3 \sqrt{2} + \sqrt{8} = 3 \sqrt{2} + \sqrt{(4 \times 2)} = 3 \sqrt{2} + 2 \sqrt{2} = (3 + 2) \sqrt{2} = 5 \sqrt{2} [/tex]
b).
[tex]12 \sqrt{3} - 2 \sqrt{27} = 12 \sqrt{3} - 2 \sqrt{(9 \times 3)} = 12 \sqrt{3} - 2(3) \sqrt{3} = 12 \sqrt{3} - 6 \sqrt{3} = (12 - 6) \sqrt{3} = 6 \sqrt{3} [/tex]
Penjelasan dengan langkah-langkah:
[tex]3 \sqrt{2} + \sqrt{8} \\ 3 \sqrt{2} + 2 \sqrt{2} \\ 5 \sqrt{2} [/tex]
[tex]12 \sqrt{3} - 2 \sqrt{27} \\ 12 \sqrt{3} - 6 \sqrt{3} \\ 6 \sqrt{3} [/tex]
Semoga Membantu
[answer.2.content]
